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Post by gaurav on Aug 27, 2020 6:11:48 GMT
Hello.
I was revisiting the lecture notes and in L2 on page 12, I think the expectation should be cubed. Is this correct?
(It might not be important for our purpose but still.) |
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Post by Zdenek Dvorak on Aug 27, 2020 9:29:37 GMT
If you mean the appearance of E_mu[chi_alpha(mu)], no, it should indeed be as it is written there. Why do you think it should be cubed?
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Post by gaurav on Aug 27, 2020 15:15:17 GMT
I understood where I made the mistake. E_x[chi_alpha(x)]=E_y[chi_beta(y)]=1 for alpha=beta. Right?
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Post by Zdenek Dvorak on Aug 29, 2020 8:01:25 GMT
E_x[chi_alpha(x)] = 0 for all alpha\neq emptyset, and E_x[chi_emptyset(x)]=1.
However,
E_x,y[chi_alpha(x)chi_beta(y)]=E_x,mu[chi_alpha(x)chi_beta(x.mu)]=
E_x,mu[chi_(alpha+beta)(x)chi_beta(mu)] = 0 if alpha\neq beta
and = E_mu(chi_alpha(mu))=E[mu_i]^|alpha| if alpha=beta
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